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y = f(x)The graph of the linear function f is shown in thexy-plane above. The graph of the linear function g(not shown) is perpendicular to the graph offand passes throu the point (1,3). What is thevalue of g(0)?

User Goosetapa
by
3.2k points

2 Answers

3 votes

Answer : its c

Explanation

User Hend
by
3.2k points
3 votes

Answer:

g(0) = 5/2

Explanation:

The equation of a line is given by:

y = ax + b

In which a is the slope, which is given by the variation in y divided by the variation in x.

If two lines are perpendicular, the multiplication of their slopes is -1.

Line f:

Passes through the points (0,3) and (1,1).

Variation in y: 1 - 3 = -2

Variation in x: 1 - 0 = 1

Slope = -2/1 = -2.

Line g:

Perpendicular to g, so the slope is:

-2*a = -1

2a = 1

a = 1/2

So the line g has an equation given by:

y = (1/2)*x + b

Passes through the point (1,3).

This means that when x = 1, y = 3. We use this to find b.

3 = (1/2)*1 + b

b = 3 - 1/2

b = 5/2

So:

g = y(x) = (1/2)*x + 5/2

g(0) = (1/2)*0 + 5/2 = 5/2

g(0) = 5/2

User Arivero
by
3.9k points