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In triangle ABC, if c = 46, b = 47....

In triangle ABC, if c = 46, b = 47....-example-1

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d)\sin (C)=(\sin (112)\cdot46)/(47)

1) In this question, the best way to tackle it is to sketch out that triangle:

2) Let's use The Law of Sines and then perform some algebraic manipulation:


\begin{gathered} (b)/(\sin(B))=(c)/(\sin(C)) \\ (47)/(\sin(112))=(46)/(\sin (C)) \end{gathered}

So let's cross multiply then:


\begin{gathered} (47)/(\sin(112))=(46)/(\sin(C)) \\ 47\cdot\sin (C)=46\cdot\sin (112) \\ (47\cdot\sin (C))/(47)=(46\cdot\sin (112))/(47) \\ \sin (C)=(46\cdot\sin(112))/(47) \end{gathered}

And that's the answer.

In triangle ABC, if c = 46, b = 47....-example-1
User Kaffarell
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