Question

Point Q' is the image of Q(-5, 1) under a translation by 6 units to the right and 2 units down.What are the coordinates of Q'?

Answer 1

`Q^(\prime)(1,-1)`

Explanation:

The general rule for a translation by 6 units to the right and 2 units down is:

`(x,y)\rightarrow(x+6,y-2)`

This way, we'll have that:

`Q(-5,1)\rightarrow Q^(\prime)(-5+6,1-2)\rightarrow Q^(\prime)(1,-1)`

We can conclude that:

`Q^(\prime)(1,-1)`