Step-by-step explanation
From the statement, we know that the road:
• rises Δy = 6 m,
,
• over a distance Δx = 80 m.
The slope of the road (m) and gradient angle (θ) are given by:
![m=\tan(θ)=(\Delta y)/(\Delta x)\Rightarrowθ=\tan^(-1)((\Delta y)/(\Delta x))](https://img.qammunity.org/2023/formulas/mathematics/college/wqlrz94lx0k733lto6ebhw0p13rnrjnivr.png)
Replacing the data of the problem, we get:
![\theta=\tan^(-1)((6m)/(80m))\cong4.289\degree.](https://img.qammunity.org/2023/formulas/mathematics/college/jzxqojzngbuoia9zlnsqerb46b3am60a1h.png)
Answer
The gradient angle of the road is approximately 4.289°.