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what is the correct classification for the following two linear equations?-2x + y =3y = -1/2 x-2A. Parallel Lines B. Perpendicular Lines

User John Pick
by
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1 Answer

3 votes

Solution

we are given the two linear equations

First Equation


\begin{gathered} -2x+y=3 \\ \\ y=2x+3 \end{gathered}

Second Equation


y=-(1)/(2)x-2

Let mA and mB denotes the gradient of the first and second equation respectively written as


m_A\text{ and }m_B

Using the slope - intercepty form, one can see that


\begin{gathered} m_A=2 \\ \\ m_B=-(1)/(2) \end{gathered}

Now,


\begin{gathered} m_A* m_B=2*-(1)/(2) \\ \\ m_A* m_B=-1 \end{gathered}

Therefore, the lines are Perpendicular

Option B

User Blair Davidson
by
7.8k points

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