Given:
The cost of bronze zebra is $5.75.
The shipping charge is $4.25.
The total price is $62.
Let us assume that the cost of a stuffed hippo is 'x' dollars, then the cost of 8 such hippos will be,
![\begin{gathered} =\text{ Number of hippos}\cdot\text{ Price of one hippo} \\ =8\cdot x \\ =8x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/dnkytta5hxi8li1rmjewt8cgmmmulf1yst.png)
The total cost must be equal to the sum of the cost of 8 hippos, 1 zebra, and the shipping charges,
![62=8x+5.75+4.25](https://img.qammunity.org/2023/formulas/mathematics/college/zgbz0rwmk9hyiosna37ejpt9lxnkwp9snf.png)
Simplify the equation to obtain the value of 'x' as follows,
![\begin{gathered} 62=8x+10 \\ 8x=62-10 \\ x=(52)/(8) \\ x=6.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/arlebliewm5a886p04xiqbzy3uv5uepb5e.png)
Thus, the cost is $6.5 per stuffed hippo.