Question

Suppose that the function h is defined, for all real numbers, as follows.1if x #2h(x)=if x=2Find h(-5), h (2), and h (4).h(-5) = 08h (2) = 0h(4) = 0010XG?

Answer 1

Given,

The expression of the function is,

`h(x)=\begin{cases}{-(1)/(4)x-1,\text{ if x}2} \\ {} \\ 1,\text{ if x }=2{}\end{cases}`

The value of h(-5) is,

`h(-5)=-(1)/(4)(-5)-1=(5)/(4)-1=(5-4)/(4)=(1)/(4)`

The value of h(2) is,

`h(2)=1`

The value of h(4) is,