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I really need help solving this practice from my ACT prep guideIt is related to trigonometry

I really need help solving this practice from my ACT prep guideIt is related to trigonometry-example-1

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First let's make a graph to understand the situation.

Now let's calculate the value for x, using the trigonometric relation of the tangent.


\begin{gathered} \tan 56=x/150 \\ x=150\cdot\tan 56 \\ x=222.38\text{ ft} \end{gathered}

In a similar way we will calculate the value of y


\begin{gathered} \tan 32=y/150 \\ y=150\cdot\tan 32 \\ y=93.73 \end{gathered}

The total height of the building would be the sum of the x and y values.


\begin{gathered} d=x+y \\ d=316.1\text{ ft} \end{gathered}

To the nearest tenth of a foot, the building is 316.1 feet tall.

I really need help solving this practice from my ACT prep guideIt is related to trigonometry-example-1
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