Question

Using a table of values, determine the solution to the equation below to the nearest fourth of a unit.2x - 4 = 3-x + 1A. x=2.5B. x=1C. x=2D. x= 3.25

Answer 1

The equation is:

`2x-4=3^(-x)+1`

Now we can evaluate the posible values of x so:

for x=2.5

`2(2.5)-4=3^(-2.5)+1`

so now we operate:

`\begin{gathered} 5-4=0.06+1 \\ 1=0.06+1 \\ 0\approx0.06 \end{gathered}`

For x=1

`2(1)-4=3^(-1)+1`

Now we operate:

`\begin{gathered} 2-4=0.33+1 \\ -2\\e1.33 \end{gathered}`

for x=2

`\begin{gathered} 2(2)-4=3^(-2)+1 \\ 4-4=0.11+1 \\ 0\\e1.11 \end{gathered}`

and for x=3.25

`\begin{gathered} 2(3.25)-4=3^(-3.25)+1 \\ 6.5-4=0.02+1 \\ 2.5\\e1.02 \end{gathered}`

So the clousest one is the option A