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Given: BC = AD and BC || AD.Prove: ABECADEA.StepStatementReason1BCADBC | ADGiventryType of StatementBEDANote: AC and BD are segments

Given: BC = AD and BC || AD.Prove: ABECADEA.StepStatementReason1BCADBC | ADGiventryType-example-1
User Jon Wei
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∆BEC =~ ∆ DEA

Then

Statements. Reason

BC=~ AD Given

BC || AD. A.S.A. (angle, side ,angle)

Proof by angle ,side ,angle. A.S.A

1. Parallel lines BC||AD,. Angle

2.BC=~ AD. Side

3. Both triangles ∆ BEC , ∆DEA, shares angle 180° -E

Segments AB, and DC, are congruent

User Sunil Buddala
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