Question

Factorise2rs-4rt-6t+3s

Answer 1

Given expression:

`2rs\text{ - 4rt - 6t + 3s}`

Collect like terms:

`=\text{ 2rs - 4rt - 6t + 3s}`

Next, we bring the common terms:

`=\text{ 2r(s - 2t) -3(2t - s)}`

Re-writing the expression:

`=\text{ -2r(2t - s) -3(2t -s)}`

Since we have a common term on either side of the negative sign, we can write:

`=\text{ (-2r -3)(2t-s)}`

Answer:

`=\text{ (-2r-3)(2t -s)}`

Let us verify the answer:

`\begin{gathered} (-2r\text{ -3)(2t-s)} \\ =-2r(2t\text{ -s) -3(2t -s)} \\ =\text{ -4rt + 2rs -6t + 3s} \end{gathered}`