First of all, we have to find the mean of x values.
According to the given graph, the x values are: 0, 1, 2, 2, 3, 3, 4, 5, 6, 7.
So, the mean is
![\bar{x}=(0+1+2+2+3+3+4+5+6+7)/(10)=(33)/(10)=3.3](https://img.qammunity.org/2023/formulas/mathematics/college/mbfrcc5jjxwfkeapkw7lwc3e4lonrxpk6y.png)
The mean of x values is 3.3.
The y values are: 2, 2, 3, 4, 4, 4, 5, 6, 8, 9.
The mean would be
![\bar{y}=(2+2+3+4+4+4+5+6+8+9)/(10)=(44)/(10)=4.4](https://img.qammunity.org/2023/formulas/mathematics/college/l7srpvcz91grqd1x1zu52y2fvekjmd88hh.png)
The mean of y values is 4.4.
Now, we find the standard deviation for x values and y values.
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