35.5k views
4 votes
What are the solutions to the quadratic equation below? x² -2x -168=0

User Solaxun
by
8.3k points

1 Answer

2 votes

Answer:

-12 and 14.

Step-by-step explanation:

Given the quadratic equation: x² -2x -168=0​

First, we factorize the expression on the left-hand side.


x^2-2x-168=(x\text{ )(x )}

Next, we multiply the first and last term,


-168* x^2=-168x^2

We then write factors of -168.


\begin{gathered} -168=12\text{ and -14 } \\ -168=-12\text{ and 14} \\ \text{Add the factors:} \\ \text{12-14=-2} \\ -12+14=2 \end{gathered}

We pick the factors that add up to the middle term: -2


\begin{gathered} x^2-2x-168=0 \\ (x+12)(x-14)=0 \\ x+12=0\text{ or }x-14=0 \\ x=-12\text{ or x=14} \end{gathered}

The solutions to the quadratic equation are -12 and 14.

User Jorvis
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories