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Let B be between A and C. Use the Segment Addition Postulate to solve for s.Segment Addition Postulate: AB + BC = ACAB = 4s -18BC = 6s -12AC = 20a s = 6Ds = 18ONS = -12DIS= 5

1 Answer

4 votes

Given:

B be between A and C.

So,


AB+BC=AC

if :


\begin{gathered} AB=4s-18 \\ BC=6s-12 \\ AC=20 \end{gathered}

So, substite with the values of AB, BC and AC then solve for s


(4s-18)+(6s-12)=20

Combine like terms:


\begin{gathered} 4s+6s=20+18+12 \\ 10s=50 \end{gathered}

Divide both sides by 10:


\begin{gathered} (10s)/(10)=(50)/(10) \\ \\ s=5 \end{gathered}

So, the answer is :


s=5

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