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If the input force is 20 N and the output force is 100 N, what is the actual mechanicaladvantage?
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If the input force is 20 N and the output force is 100 N, what is the actual mechanicaladvantage?

User Ianna
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\begin{gathered} F_(input)=20N \\ F_(output)=100N \\ MA=? \\ MA=(F_(output))/(F_(input))=(100N)/(20N)=5 \\ MA=5 \\ The\text{ mechanical advantage is 5} \\ \\ Question\text{ 2\rparen} \\ W_(input)=380J \\ W_(output)=500J \\ \eta=? \\ \eta=(W_(output))/(W_(input))=(500J)/(380J)=1.316=131.6 \\ The\text{ efficiency is 131.6\%} \end{gathered}

If the input force is 20 N and the output force is 100 N, what is the actual mechanicaladvantage-example-1
If the input force is 20 N and the output force is 100 N, what is the actual mechanicaladvantage-example-2
User Saeed Khalafinejad
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