Question

Write the equation of a line that has a slope of 3x - 4y = 12 and passes through the point (8, 8)

Answer 1

first of all we have to find the slope

3x - 4y = 12

-4y = 12 - 3x

y = -3 + ³/₄ x

y = ³/₄x - 3

so the slope is ³/₄

now the equation is :

y-y₁ = m (x-x₁)

y-8 = ³/₄ (x-8)

y-8 = ³/₄ x - 6

y = ³/₄ x -6 + 8

y = ³/₄x + 2