Question

A car traveling at 4.4 m/s accelerates at the rate of +0.63 m/s2 for an interval of 5.4 s. Find vf.

Answer 1

Given data

*The given speed of the car is u = 4.4 m/s

*The given acceleration of the car is

`a=+0.63m/s^2`

*The given time is t = 5.4 s

The formula for the final speed of the car is given as

`v_f=u+at`

Substitute the known values in the above expression as

`\begin{gathered} v_f=(4.4)+(0.63)(5.4) \\ =7.80\text{ m/s} \end{gathered}`

Hence, the final speed of the car is 7.80 m/s