Question

A line with a slope of -10/11passes through the point (-11 ,10). What is its equation in slope- intercept form Write your answer using integers, proper fractions , and improper fractions in simplest, i need help

Answer 1

We have a line of which we know the slope m = -10/11 and one point (x0,y0) = (-11,10).

We have to find its equation in slope-intercept form.

We can start by writing the equation in slope-point form with the information we have and rearrange to express it in slope-intercept form:

`\begin{gathered} y-y_0=m(x-x_0) \\ y-10=-(10)/(11)(x-(-11)) \\ y-10=-(10)/(11)(x+11) \\ y=-(10)/(11)x-(10)/(11)\cdot11+10 \\ y=-(10)/(11)x-10+10 \\ y=-(10)/(11)x \end{gathered}`

The equation in slope-intercept form is y = -(10/11)*x.

Answer: y = -(10/11)*x