Question

A machine raises an object of weight 1200 N through a distance of 5.0 m. What is its efficiency if the energy input is 8 000 J?

Answer 1

Given

Weight of the object, W=1200 N

Distance travelled , s=5.0 m

Input energy, Q=8000J

To find

The efficiency of the engine

Step-by-step explanation

The efficiency is the ratio of work done to the input energy

So

`\begin{gathered} \eta=(W.s)/(Q) \\ \Rightarrow\eta=1200*(5)/(8000) \\ \Rightarrow\eta=0.75 \end{gathered}`

Conclusion

The efficiency is 0.75