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A box contains 4 chocobars and 4 ice-creams. Tom eats 3 of them one after another. What is the probability of sequentially choosing 2 chocobars and 1 ice-cream? Correct to 2 decimal places.

User Muniro
by
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1 Answer

6 votes

Given:

The number of choco bars = 4.

The number of ice creams = 4.

Aim:

We need to find the probability of sequentially choosing 2 choco bars and 1 ice cream.

Step-by-step explanation:

The total items in the box =4+4 =8.


n(S)=8

Let A be the event that chooses 2 choco bars.

There are 4 choco bars in the box.


n(A)=4

The probability of choosing 2 choco bars.


P(A)=(n(A))/(n(S))

Substitute known values,


P(A)=(4)/(8)=(1)/(2)

After taking 2 chocobars, the number of items in box = 8-2 =6.


n(S_1)=6

Let B be the event that takes one ice cream from the box.

There are 4 ice creams in the box.


n(B)=4

The probability of choosing one ice cream.


P(B)=(n(B))/(n(S_1))

Substitute known values.


P(B)=(4)/(6)=(2)/(3)

The probability of sequentially choosing 2 choco bars and 1 ice-cream


=P(A)* P(B)
=(1)/(2)*(2)/(3)
=0.33

Final answer:

The probability of sequentially choosing 2 choco bars and 1 ice cream is 0.33.

User Rollsbean
by
9.0k points
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