In the question, we are required to find the average number of pictures taken by the cameras per time.
We can get this by the equation below:
![\text{Average picture(s) per time =}\frac{\text{ Total pictures taken}}{\text{ total time taken}}](https://img.qammunity.org/2023/formulas/mathematics/college/vw8572dxqu88ddvnhqxzc6tqe9h89lqmnz.png)
First Camera:
![\text{Average picture(s) per time = }(80)/(10)=8\text{pictures per second}](https://img.qammunity.org/2023/formulas/mathematics/college/ghp84qg9lhlv9aojm66xstjtjyha5bu11b.png)
Second Camera:
![\text{Average picture(s) per time = }(45)/(5)=9\text{pictures per second}](https://img.qammunity.org/2023/formulas/mathematics/college/eidub0dyd0ooiqni8er5pw1tfhnvglnwm8.png)
Third Camera:
![\text{Average picture(s) per time = }(56)/(8)=7\text{pictures per second}](https://img.qammunity.org/2023/formulas/mathematics/college/2u39r8kupmw41r4u9icq7mte95r09xo9sg.png)
The fastest camera is that which takes the most pictures in a time interval as compared to the others.
In this case, THE SECOND CAMERA