Question

1) w(n)=n-5; Find w(4)2) g(x)= -[x]: Find g(-4)3) h(n) = 3 | n + 2|; Find h(5)4)h(a) = a^3 + 3a^2; find h(-5)5)p(n)=n^2 - 4n; find p(3)

Answer 1

1) w(n)=n-5; Find w(4)

2) g(x)= -[x]: Find g(-4)

3) h(n) = 3 | n + 2|; Find h(5)

4)h(a) = a^3 + 3a^2; find h(-5)

5)p(n)=n^2 - 4n; find p(3)​

Part 1)

we have

w(n)=n-5

Remember that

w(4) is the value of the function w(n) for n=4

so

substitute the value of n=4 in the equation

w(4)=4-5

w(4)=-1

Part 2

g(x)= -[x]

Find h(5)

For x=5

g(5)=-[5]

g(5)=-5

we have

Part 3

we have

h(n) = 3 | n + 2|

Find h(5)

For n=5

h(5)=3 | 5 + 2|

h(5)=3 | 7|

h(5)=21

Part 4

h(a) = a^3 + 3a^2

Find h(-5)

For a=-5

substitute

h(-5)=(-5)^3+3(-5)^2

h(-5)=-125+75

h(-5)=-50

Part 5

p(n)=n^2 - 4n

Find p(3)

For n=3

substitute

p(3)=3^2-4(3)

p(3)=9-12

p(3)=-3