SOLUTION:
Step 1 :
In this question, we have that Jessica bought a desktop computer and a laptop computer.
Before finance charges, the laptop cost $450 less than the desktop.
This means that:
![\begin{gathered} \text{Let L = cost of the laptop = D - 450} \\ D=\text{ cost of the desktop } \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/np348lc0ajcxycugxogpd9w7b3twz99xao.png)
Step 2 :
The total finance charge for one year is given by :
![\begin{gathered} (\text{ 6.5 \% of D ) + ( 9 \% of L ) = 409} \\ (\text{ 0. 065 x D ) + ( 0.09 X ( D - 450 ) ) = 409} \\ 0.065\text{ D + 0.09 D - 40. 5 = 409} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1km26a9n8sqbtb28omhxl6kbj1ckj5xbce.png)
![\begin{gathered} \text{Simplifying further, we have that:} \\ 0.065\text{ D + 0.09 D = 409 + 40. 5} \\ 0.155\text{ D = 449.5} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8oq419xd3sv1rw3obyx1y2iqivninvs5up.png)
![\begin{gathered} \text{Dividing both sides by 0.155, we have that:} \\ D\text{ =}\frac{449.\text{ 5}}{0.155} \\ D\text{ = }2900 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/e1yxcr4zyrmag325763wgllr75yku3i1z3.png)
Step 3:
Recall that the cost of the Laptop = D - 450
This means that :
![2900\text{ - 450 = 2450}](https://img.qammunity.org/2023/formulas/mathematics/college/cwlhhfvxkshqyv8nb2dif4r3nmqcd7ttbr.png)
Check:
![\begin{gathered} (\text{ 6. 5\% of 2900 ) + ( 9 \% of 2450 ) } \\ =\text{ 188. 50 + 220. 50 = \$ 409} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/2anuktvsjjkgc331knfy3h15izojrcxjdb.png)
CONCLUSION:
The cost of the Desktop before the finance charges = $ 2900
The cost of the Laptop before the fiance charges = $ 2450.