Given:
Weight = 169.8 N
Angles: 60°,30°
x-coordinate:
TACx = TBCx
TAC cos 60 = TBC cos 30
TAC 1/2 = TBC √3/2
TAC = TBC √3 (1)
y-coordinates
TCD = 169.8 N
TACy + TBCy = TCD
TAC sin 60 + TBC sin 30 = 169.8
TAC (√3/2) + TBC (1/2) = 169.8
TAC √3 + TBC = 339.6 (2)
Substitute Equation (1) in equation (2)
(TBC √3) √3 + TBC = 339.6
3TBC + TBC= 339.6
4 TBC = 339.6
TBC= 339.6/4
TBC= 84.9N
TAC =TBC √3
TAC = 84.9 √3 N
Answers:
TAC (left cable) = 84.9 √3 N
TBC (right cable) = 84.9 N
TCD (bottom cable) = 169.8 N