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A glass blower can form 8 simple vases or 2 elaborate vases in an hour. In a work shift of no more than 8 hours, the worker must form at least 40 vases.

a. Let s represent the hours forming simple vases and e the hours forming elaborate vases. Write a system of inequalities involving the time spent on each type of vase.
b. If the glass blower makes a profit of $30 per hour worked on the simple vases and $35 per hour worked on the elaborate vases, write a function for the total profit on the vases.
c. Find the number of hours the worker should spend on each type of vase to maximize profit. What is that profit?

1 Answer

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Answer:


\textsf{a)} \quad \begin{cases}s+e \leq 8\\8s+2e \geq 40\end{cases}


\textsf{b)} \quad y = 30s + 35e

c) 4 simple vases and 4 elaborate vases maximize profit.

The maximum profit is $260.

Explanation:

Given information:

  • A glass blower can form 8 simple vases or 2 elaborate vases in an hour.
  • In a work shift of no more than 8 hours, the worker must form at least 40 vases.

Part (a)

Define the variables:

  • Let s = the number of hours forming simple vases.
  • Let e = the number of hours forming elaborate vases.

Create a system of inequalities using the given information and defined variables:


\begin{cases}s+e \leq 8\\8s+2e \geq 40\end{cases}

Part (b)

Given information:

  • $30 = profit per hour for the simple vases.
  • $35 = profit per hour for the elaborate vases.

Let y be the total profit in dollars:


y = 30s + 35e

Part (c)


\begin{cases}s+e \leq 8\\8s+2e \geq 40\end{cases}

To find the number of hours the worker should spend on each type of vase to maximize profit, find the point of intersection of the two equations.

Isolate e in the first equation:


\implies e\leq8-s

Isolate e in the second equation:


\implies 2e \geq 40-8s


\implies e \geq 20-4s

Equate the two expressions for e and solve for s:


\implies 8-s=20-4s


\implies 3s=12


\implies s=4

Therefore, the number of hours the worker should spend on each type of vase to maximize profit is:

  • Simple vases = 4 hours.
  • Elaborate vases = 4 hours.

Substitute the values of s and e into the function from part (b):


\implies y=30(4)+35(4)


\implies y=120+140


\implies y=260

Therefore, the maximum profit is $260.

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