You have the following inequalities:
-2y > 2
y/3 < - 1
3y < 2y + 3
In order to graph the previous inequalities on the number line, you first solve the previous inequalities:
-2y > 2 divide both sided by -2
y < 2/(-2) where you take into account that the division by a negative number change the sense of the inequality
y < -1
y/3 < -1 multiply both sides by 3
y < -1(3)
y < -3
3y < 2y + 3 subtract 2y both sides
3y - 2y < 3
y < 3
THe following image is a sketch of the previous solutions on the number line:
where the orange line is the first solution, the red line is the second solution, and the green line is the third solution