Question

Score on last try: 0 of 7 pts. See Details for more.> Next questionGet a similar questionYou can retry this question belowWater Pressure ApplicationIn certain deep parts of oceans, the pressure of sea water, P, in pounds per square foot, at a depth5of d feet below the surface, is given by the following equation P = 15+ d. Use this equation to13complete the statements below. Round your answers to the nearest tenth as needed.PThe pressure of sea water is 100 pounds per square foot at a depth of 1surface of the water.Ifeet below the+The pressure of sea water is 67.5x pounds per square foot at a depth of 80 feet below thesurface of the water.Question Help: D Video D Post to forum

Answer 1

`P=15+(5)/(13)d`

1. The pressure of sea water is 100 pounds per square foot (P=100) at a depth (d):

`100=15+(5)/(13)d`

Solve d:

`\begin{gathered} \text{Subtract 15 in both sides of the equation:} \\ 100-15=15-15+(5)/(13)d \\ \\ 85=(5)/(13)d \\ \\ \text{Multiply both sides of the equation by 13/5:} \\ (13)/(5)\cdot85=(13)/(5)\cdot(5)/(13)d \\ \\ 221=d \\ \\ d=221 \end{gathered}`

Then, The pressure of sea water is 100 pounds per square foot at a depth of 221 feet below the surface of the water

2. Find the pressure of the water (P) when d=80

`\begin{gathered} P=15+(5)/(13)(80) \\ \\ P=15+(400)/(13) \\ \\ P=(195+400)/(13) \\ \\ P=(595)/(13) \\ \\ P=45.8 \end{gathered}`

Then, the pressure of sea water is 45.8 pounds per square foot at a depth of 80 feet below the surface of the water