Question

In the equation:4NH3 + 5O2 → 4NO + 6H2OFind the volume of oxygen that reacts with 1.12 L of NH3.

Answer 1

Given the reaction:

`4NH_3+5O_2\to4NO+6H_2O`

As you can notice, the reaction is actually balanced. So, we could use the coefficients of the reaction to find the volume of oxygen that reacts with 1.12 L of NH3.

First of all, remember that the Molar Volume statement tells us that at standard temperature and pressure, 1 mole of any gas occupies 22.4 L.

Then,

`1.12LNH_3\cdot(1molNH_3)/(22.4LNH_3)=0.05molesNH_3`

This is the amount of NH3 that we actually have. Now, according to the coefficients of the reaction, we can notice that 5 moles of Oxygen reacts for each 4 moles of NH3. So,

`0.05\text{molesNH}3\cdot\frac{5\text{molesO}2}{4\text{molesNH}3}=0.0625\text{molesO}2`

Now, using again the fact that 1 mole of any gas occupies 22.4 L, we obtain:

`\text{0}.0625\text{molesO}2\cdot\frac{22.4LO_2}{1\text{molO}2}=1.4LO_2`

Therefore, the answer is 1.4L.