Since the triangles are similar that means that:

where x is the factor that tajes triangle GHK to triangle JMP. Solving for x we have:

Now, we know that a similarity transformation takes the perimter to the original tirangle to the new one like:

where P' is the perimeter of triangle JMP and P the perimeter of triangle GHK. Then:

Therefore the perimter of triangle JMP is 58.5 inches.