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BEUse substitution to solve.f2x2 = 5 + y4y = -20 + 8x2Solve the first equation for y and substitute it into the second equation. The resulting equati4y = 16x2 - 608x2 - 20 = -20 + 8x22x2 = 5 + 2x2 - 5

BEUse substitution to solve.f2x2 = 5 + y4y = -20 + 8x2Solve the first equation for-example-1
User Arif Dewi
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1 Answer

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Given that:


\begin{gathered} 2x^2=5+y \\ 4y=-20+8x^2 \end{gathered}

From the first equation,


y=5-2x^2

Substitute the obtained value of y into the second equation.


\begin{gathered} 4(5-2x^2)=-20+8x^2 \\ 20-8x^2=-20+8x^2 \end{gathered}

So, it has infintely many solutions.

Solutions are of the form:


(x,y)=(x,5-2x^2

where x is any real number.

User Ann Joseph
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