there is not integer whose square is 26, therefore, 26 is not a perfect square
Step-by-step explanation
a square number or perfect square is an integer that is the square of an integer
![a=b^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/arbuofxp0syfpdhsrqtj7licz0cg25nddl.png)
if b is a integer, then a is a perfect square
Step 1
so
let
a= 26
now, replace and solve for b, if b is a integer then a is a perfect square
![\begin{gathered} a=b^2 \\ 26=b^2 \\ square\text{ root in both sides} \\ √(26)=√(b^2) \\ √(26)=b \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ed1jofq65olces6ccq1ej5wjpx9z40sk56.png)
the square root of 26 is not an integer, so
26 is not a perfect square
so, the answer is
there is not integer whose square is 26, therefore, 26 is not a perfect square
I hope this helps you