Question

Find p where f(x) = 2x ^ 3 + 5x ^ 2 + px + 8 where f(- 2) = 10

Answer 1

Step-by-step explanation

Given the function

`f\mleft(x\mright)=2x^3+5x^2+px+8`

We can find the value of p when f(-2 )=10 below;

Therefore, we will have;

`\begin{gathered} f(-2)=2(-2)^3+5(-2)^2+(-2)p+8=10 \\ -16+20-2p+8=10 \\ -4-2p+8=10 \\ -2p+4=10 \\ -2p=10-4 \\ -2p=6 \\ p=(6)/(-2) \\ p=-3 \end{gathered}`

Answer: p = -3