cost of one daylily= $4
cost of one bunch= $ 9
Step-by-step explanation
Step 1
Let x represents the cost of one daylily
Let y represents the cost of one bunch
then
Kali spent $132 on 6 daylilies and 12 bunches of ornamental grass.
in math terms

and
Asanji spent $83 on 14 daylilies and 3 bunches of ornamental grass

Step 2
solve for x and y
multiply equation (2) by -4 and add the result to equation(1)

now, to find y, replace x equation (2) and isolate y

so
cost of one daylily= $4
cost of one bunch= $ 9