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Let A = {a,b,c), B = {4,5,6), and/= {(a ,6), (b,4), (c,6)). Is f a function from A to B? Explain.

User Volk
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The condition for a group of paired values to be a function is that for each value of the independent variable exists one and only one value of the dependant variable.

In this case, A is the group of points that represent the independent variable, and B, the dependent variable.

As each value of A has one and only one value of B, f is a function from A to B.

The inverse is not true, as 6 would have 2 values (a and c) in the image (A).

A is the domain of the independent variable.

f is the function that transform the values present in the group A in some of the elements of the image, that is group B.

The conditions for that relation to be a function is that each of the values in the domain has one and only one value in the image.

Let A = {a,b,c), B = {4,5,6), and/= {(a ,6), (b,4), (c,6)). Is f a function from A-example-1
User Moscas
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