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Find the exact length, in units, of the hypotenuse of the right triangle, shown below. Write your answer in simplified radical form.

Find the exact length, in units, of the hypotenuse of the right triangle, shown below-example-1

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Right Triangles

A right triangle is identified because it has an angle of 90° (marked as a little square).

In a right triangle, there is a larger side called the hypotenuse, and two shorter sides called the legs.

Each one of the acute angles in a right triangle has an adjacent leg and an opposite leg. For example, the angle of 45° given in the figure has 15 as the adjacent leg. The hypotenuse is below it, and we'll call it H.

There is a trigonometric ratio called the cosine that relates the adjacent leg of an angle with the hypotenuse as follows:


\displaystyle\cos \theta=\frac{\text{adjacent leg}}{\text{hypotenuse}}

Applying to the given triangle:


\cos 45^o=(15)/(H)

Solving for H:


H=(15)/(\cos45^o)=\frac{15}{\frac{\sqrt[]{2}}{2}}=15\cdot\frac{2}{\sqrt[]{2}}\cdot\frac{\sqrt[]{2}}{\sqrt[]{2}}=15\sqrt[]{2}

Hypotenuse length:


15\sqrt[]{2}

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