Factor by grouping(4y^3 + 28y^2) + (y + 7)

Question

Factor by grouping
`(4y^3 + 28y^2) + (y + 7)`

Answer 1

We have the following expression given:

`(4y^3+28y^2)+(y+7)`

We can start selecting as common factor 4y^2 and we got:

`4y^2(y+7)+(y+7)`

Now we can select y+7 as common factor and we got:

`(y+7)\left\lbrack 4y^2+1\right\rbrack`

So then our final answer would be:

`(y+7)(4y^2+1)`