The first step we need to make is to organize the data from smallest to largest. We have:

There are six scores, so there are two quartiles, each formed by 3 numbers. We have:

We need to take the middle value of each quartile. The median. We have:

The IQR is the diference between Q3 and Q1. We have:

The IQR is equal to 10. The values on this distribuition are expected to be in the range:

If a value is outside of this range, then it is an outlier. The range is:

There are no values outside this range, therefore there are no outliers.