To solve this question, we need to find the x-intercepts and the y-intercepts for each of the equations. After having these values, we will have a pair of points for one equation, and another pair of points for the other equation.
We can proceed as follows:
First case:
We can find the y-intercept if we have x = 0. Then, the y-intercept is:

Similarly, the x-intercept is (for y = 0, we then have x):

Then, for the first equation, we have that the y-intercept is (0, 3), and the x-intercept is (12,0). These two points are important to graph this equation.
Second Case:
We can proceed in the same way to find the y-intercept and the x-intercept.

Then, the y-intercept is (0, -1).
The x-intercept is

Hence, the x-intercept is (4/3, 0).
Having all of this information, we can graph the first line using the points:
The y-intercept is (0, 3)
The x-intercept is (12,0)
And then, we can graph the second line using the points:
The y-intercept is (0, -1)
The x-intercept is (4/3, 0).
The graph is
And the solution is the point where both lines intercept each other, that is the point x = 4, and y = 2.
If we see the answer choices we have that the answer is the second graph.