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Zac purchased a new car for $23995 . The value of the car linearly depreciated to $9300 over 10 years . Write a linear equation to represent the value of Y of zacs car ( in dollars ) after X years since it’s purchase

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Given that:

- The initial value of the car was $23995.

- Its value linearly depreciated to $9300 over 10 years.

- The variable "y" represents the value of Zac's car (in dollars) and "x" represents the number of years since it’s purchased.

You need to remember the Slope-Intercept Form of the equation of a line:


y=mx+b

Where "m" is the slope of the line and "b" is the y-intercept.

In this case, the value of "b" is the initial value of the car when it was purchased by Zac:


b=23995

By analyzing the data given in the exercise, you can identify this point:


(10,9300)

Where:


\begin{gathered} x=10 \\ y=9300 \end{gathered}

Therefore, you can substitute all the known values into the following equation and solve for the slope "m":


y=mx+b

Then, you get:


\begin{gathered} 9300=m(10)+23995 \\ \\ 9300-23995=10m \end{gathered}


\begin{gathered} -14695=10m \\ \\ (-14695)/(10)=m \\ \\ m=-1469.5 \end{gathered}

Knowing "m" and "b", you can set up the following equation to represent this situation:


y=-1469.5x+23995

Hence, the answer is:


y=-1469.5x+23995
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