y = -3x - 5 Eqn(1)
x - y = -3 Eqn(2)
First we are going to isolate y on each equation to find some points to plot the graphs.
Eqn(1)
As it is not needed to isolate y, we find some points to plot.
x y
0 -3(0) - 5 = -5
1 -3(1) - 5 = -8
-1 -3(-1) - 5 = -2
Points for plotting: (0,-5), (1,-8), (-1,-2)
Eqn(2)
Isolating y, we have:
x = y - 3 (Subtracting y from both sides of the equation)
x + 3 =y (Adding 3 to both sides of the equation)
Then, we find some points to plot
x y
0 (0) +3 = 3
1 (1) +3 = 4
-1 (-1) +3 = 2
Plotting the equations we have:
Based on the graph the solution would be: x=-2 and y=1, as it is the intersection point.