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the perimeter of a rectangle is 54 inches the length is three more than twice the width what are the dimensions of the rectangle

User Bessarabov
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Perimeter of a rectangle = (2x length) + ( 2 x width)

if the length is 3 more than twice the width then

length = 3 +( 2x width)

substituting for the perimeter which is given as 54 inches and the length derived as above in to the equation for the perimeter. we have

54 = 2(3+(2 x w)) + 2w

54 = 6 +4w +2w

54 =6 +6w

6w = 48

6w/6 = 48/6

w = 8 inches

Substituting for w in the equation for length gives us

length = 3 + (2 x8)

L= 3+16

L = 18 inches

The dimesnsions of the rectangle are therefore

W = 8 inches

and

L = 18 inches

User Ashiina
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