Question

FIND THE HEIGHT OF THE trapezoid A =51 CM2

Answer 1

We use the formula of the area of a trapezoid

`A=((B+b)h)/(2)`

where A is the area, B and b are bases of the trapezoid and h the height

we can replace values like area, and bases

`51=((10+7)h)/(2)`

simplify

`51=(17h)/(2)`

multiply on both sides to remove denominator 2

`\begin{gathered} 51*2=(17h)/(2)*2 \\ \\ 102=17h \\ 17h=102 \end{gathered}`

and divide between 17 to find h

`\begin{gathered} h=(102)/(17) \\ \\ h=6 \end{gathered}`

the height of trapezoid is 6cm