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The perimeter of a triangle is 72 cm. The longest side is 4 cm less than the sum of the other two sides. Twice the shortest side is 8 cm less than the longest side Fi of each side of the triangleThe perimeter of a triangle is 72 cm. The longest side is 4 cm less than the sum of the other two sides. Twice the shortest side is 8 cm less than the longest side. Find th of each side of the triangle

1 Answer

5 votes

Answer:

13 cm, 25 cm and 34 cm

Explanation:

Define the variables:

  • Let a = shortest side of the triangle.
  • Let c = longest side of the triangle.
  • Let b = other side of the triangle.

Given the perimeter of the triangle is 72 cm:

⇒ a + b + c = 72

Given the longest side is 4 cm less than the sum of the other two sides:

⇒ c = a + b - 4

Given twice the shortest side is 8 cm less than the longest side.

⇒ c = 2a + 8

Substitute the third equation into the second equation and solve for b:

⇒ c = a + b - 4

⇒ 2a + 8 = a + b - 4

⇒ a + 8 = b - 4

⇒ b = a + 12

Substitute the found expression for b and the third equation into the first equation and solve for a:

⇒ a + b + c = 72

⇒ a + (a + 12) + (2a + 8) = 72

⇒ 4a +20 = 72

⇒ 4a = 52

a = 13

Substitute the found value of a into the other expressions to find b and c:

⇒ b = a + 12

⇒ b = 13 + 12

b = 25

⇒ c = 2a + 8

⇒ c = 2(13) + 8

⇒ c = 26 + 8

c = 34

Therefore the lengths of the sides of the triangle are:

  • 13 cm
  • 25 cm
  • 34 cm
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