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Find x to the nearest 100th if sin x = 7/8

User Locksley
by
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1 Answer

0 votes

Answer:

x = 61.04°

Explanation:

Given:


\sin x=(7)/(8)

Take the arcsin of both sides of the equation.


\begin{gathered} \arcsin(\sin x)=\arcsin((7)/(8)) \\ \implies x=61.04\degree \end{gathered}

The value of x is 61.04° to the nearest 100th.

User Cory Shaw
by
7.8k points

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