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Find the perimeter. The shape consists of a squareand half a circle. Use = 3.14.

Find the perimeter. The shape consists of a squareand half a circle. Use = 3.14.-example-1

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Given:

The diameter of the semicircle is d= 2in.

The side of the square is a= 2in.

Required:

We need to find the perimeter of the given shape.

Step-by-step explanation:

Recall that the perimeter of a two-dimensional figure is the distance covered around it.

The perimeter of the given shape is the sum of the length of arc of the semicircle and 3 sides of the square.


Recall\text{ that the length of the arc of the semicircle is }\pi r.

The perimeter of the given shape is


P=\pi r+3a

Consider the radius formula.


r=(d)/(2)

Substitute d =2 in the formula


r=(1)/(1)=1\text{ in}
Substitute\text{ }\pi=3.14,r=1\text{ and a=2 in the formula }P=\pi r+3a.
P=3.14(1)+3(2)
P=9.14in

Final answer:

The perimeter of the given shape is 9.14in.

Find the perimeter. The shape consists of a squareand half a circle. Use = 3.14.-example-1
User Benjamin White
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