Question

Boyle's Law states that the pressure exerted by a gas held at a constant temperature varies inversely with the volume of the gas. At a volume of 2 L the pressure of a gas is 150 kPa. If the volume of the gas is 6 L, what would be the pressure of the gas in kPa?

Answer 1

`\text{Pressure = 50 kPa}`

Here, we want to use the proportionality to get the value of the pressure of the gas

From the question, we have it that the pressure and the volume are inversely related at constant temperature

Let us have the pressure as P, volume as V and temperature as T

Thus, we have the relationship as follows;

`\begin{gathered} P\text{ }\propto\text{ }(1)/(V) \\ PV\text{ = T} \\ \\ At\text{ V = 2 and P = 150} \\ T\text{ = 150}*2\text{ = 300} \\ \end{gathered}`

When V = 6, we have P as follows;

`\begin{gathered} 6* P\text{ = 300} \\ P\text{ = }(300)/(6) \\ P\text{ = 50 KPa} \end{gathered}`