First we must obtain the relationship between the grade, the mean and the standard deviation of exam A
![\begin{gathered} z=\frac{x-\operatorname{mean}}{\sigma} \\ z_A=(508-500)/(40) \\ z_A=0.2 \\ \end{gathered}]()
Now we have to find the required score for exam B to reach the same ratio factor z

As seen in the calculations, Nevaeh must score 354 on Exam B to equal the score on Exam A