Explanation
We are given the following:
![\begin{gathered} A(-4,6) \\ B(6,6) \\ C(1,-3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/603uwrrrjjfh53g7ugs2039si5gdkijk2z.png)
We are required to determine whether or not triangle ABC is an equilateral triangle.
We know that an equilateral triangle is a triangle with all sides equal.
We also know that the distance between two points is given as:
![Distance=√((y_2-y_1)^2+(x_2-x_1)^2)](https://img.qammunity.org/2023/formulas/mathematics/college/u53y6cylyxnf8rrglvlem5gn72wgjj4l4z.png)
- The distance AB becomes:
![\begin{gathered} A(-4,6)\to(x_1,y_1) \\ B(6,6)\to(x_2,y_2) \\ AB=√((y_2-y_1)^2+(x_2-x_1)^2) \\ AB=√((6-6)^2+(6-(-4))^2) \\ AB=√(0^2+10^2)=√(0+100)=√(100) \\ AB=10\text{ units } \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bu6hyeedtpxq327hbu9fdabqnu35pukotz.png)
- The distance BC becomes:
![\begin{gathered} B(6,6)\to(x_1,y_1) \\ C(1,-3)\to(x_2,y_2) \\ BC=√((y_2-y_1)^2+(x_2-x_1)^2) \\ BC=√((-3-6)^2+(1-6)^2) \\ BC=√((-9)^2+(-5)^2)=√(81+25)=√(106) \\ BC\approx10.3\text{ units} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/48w0pzfie7fs336ag1ddx9fw8x859x1q07.png)
Hence, the answer is:
![\text{ No, because BC is longer than AB}](https://img.qammunity.org/2023/formulas/mathematics/college/orzpqlvv1wbudqd5n3w30ycgol1sh41ova.png)
Option C is correct.