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What is the length (magnitude) of the vector (2,-1)? O A. 1 B. -2 O C. 2 D. D. 5

User Dorserg
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1 Answer

5 votes

We are given the following vector


v=(2,-1)

The magnitude of a 2-dimensional vector is given by


|v|=√(x^2+y^2)

Substitute the given points into the above formula


\begin{gathered} |v|=√((2)^2+(-1)^2) \\ |v|=√(4+1) \\ |v|=√(5) \end{gathered}

Therefore, the magnitude of the vector (2, -1) is √5


|v|=√(5)

User Neet
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