ANSWER
![\begin{equation*} -8 \end{equation*}](https://img.qammunity.org/2023/formulas/mathematics/college/kixzp1lj6c0y5ayvo0msp5952us1zjojvk.png)
Step-by-step explanation
To find the slope of the function at the given point, we have to apply the formula:
![slope=\lim_(h\to0)(f(a+h)-f(a))/(h)](https://img.qammunity.org/2023/formulas/mathematics/college/z0mvuatbr2a0hd58cxgf05h2cfqdacafr0.png)
where a = x-coordinate of the point.
From the question, a = 2.
Therefore, the slope of the function at x = 2 is:
![\begin{gathered} slope=\lim_(h\to0)(2(2+h-4)^2-2(2-4)^2)/(h) \\ \\ slope=\lim_(h\to0)(2(h-2)^2-2(-2)^2)/(h)=\lim_(h\to0)(2(h^2-4h+4)-8)/(h) \\ \\ slope=\lim_(h\to0)(2h^2-8h+8-8)/(h)=\lim_(h\to0)(2h^2-8h)/(h) \\ \\ slope=\lim_(h\to0)2h-8=0-8 \\ \\ slope=-8 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mamz8f5g00e8vkakrltd7p64sby0ma5tbq.png)
That is the slope at the given point.